Anar

vac.html

@@ -48,19 +48,21 @@
 It sounds more complicated than it is, since its describing multiple scenarios, however you can
 take it from the last scenario, and sortve trace the steps backwards so to speak...
 
-The last scenario, we said we could take that `(*database>pack)` to access the `buffer` member of the `Anar` struct.
+The last scenario, we said we could take that `(*database->pack)` to access the `buffer` member of the `Anar` struct.
 
 In C, when you mix (.) period and (->) arrow operators with dereferencing, parentheses adheres the order of
 operations. Without parentheses, you can’t directly use the (.) operator on a pointer without first dereferencing it.
 
 For example, consider  *database->pack.nar.buffer   Here’s how the C compiler interprets it:
 
 `database->pack`  is a pointer to Vac.
-`database->pack.nar`  is an invalid syntax because (->) should be used for accessing members from a pointer
-to a struct, and `nar` is not a member of ` Vac * `  but of  `Vac`
+`database->pack.nar`  is an invalid syntax.
 
-To correctly access buffer, you need to dereference `database->pack` to get the `Vac` struct.
-Access the `nar` member of the `Vac` struct. And access the `buffer` member of the `Anar` struct (as we said when describing the last scenario)
+First, (->) is used for accessing members from a pointer to a struct. And we want to use `nar`, however is not a member
+of ` Vac * `. It is a member of `Vac`.
+
+We have to correctly access `buffer` of the `Anar` struct, and `nar` from the rest, you need to dereference
+`database->pack` to get the `Vac` struct. Once you understand that, it should make sense.
 
 So the correct syntax in that particular situation would be:
 <span class="alt-text">
@@ -71,5 +73,4 @@
 <span class="alt-text">
   Vac *exac = *database-&gt;pack;</span>
 
-Which would allow you to use it as `exac-&gt;nar.buffer`
-
+Which would allow you to use it as `exac-&gt;nar.buffer`, and is just one example of something you might do.