Feature/protostar ivc #25
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han0110
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Sep 19, 2023
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| let powers_of_zeta_first_poly = powers_of_zeta_poly((l_sqrt-1).ilog2() as usize, zeta); | ||
| let powers_of_zeta_second_poly = powers_of_zeta_poly((l_sqrt-1).ilog2() as usize, zeta.pow(&[l_sqrt as u64])); | ||
| let powers_of_zeta_poly = powers_of_zeta_first_poly.add(&powers_of_zeta_second_poly); |
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I think this should be concatenated instead of added
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| let zeta_cross_term_poly = evaluate_zeta_cross_term_poly( | ||
| l_sqrt * l_sqrt, | ||
| *num_alpha_primes, | ||
| accumulator, | ||
| incoming, | ||
| ); |
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Since the constraint for zeta becomes different, I think we need another function for it
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done. i m not sure about the boundary conditions on the cross terms when we deal with zeta_power_lsqrt
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| let powers_of_zeta_sqrt1_constraint = powers_of_zeta_constraint(zeta, powers_of_zeta_sqrt); | ||
| let zeta_sqrt1_products = products(&poly_set.preprocess, &powers_of_zeta_sqrt1_constraint); | ||
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| let powers_of_zeta_sqrt2_constraint = powers_of_zeta_constraint(zeta.pow(l_sqrt as u32), powers_of_zeta_sqrt); | ||
| let zeta_sqrt2_products = products(&poly_set.preprocess, &powers_of_zeta_sqrt2_constraint); | ||
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| let zeta_products = iter::empty() | ||
| .chain(zeta_sqrt1_products.iter().cloned()) | ||
| .chain(zeta_sqrt2_products.iter().cloned()) | ||
| .collect_vec(); |
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We'd need another poly and challenge by zeta_to_l and adopt the same constraint on them.
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will this another poly help to recompute all the powers of beta from the square root terms? what is this challenge zeta_to_l?
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review1 sqrt CV