Limitation because subprocess.run with timeout doesnt work for child processes

[bigbitbus]

I am trying to use a timeout to kill a subprocess launched via .run(timeout=); this is not supported unlike the original subprocess.run()

To reproduce:

Python 3.8.12 (default, Oct 27 2021, 12:52:48) 
[GCC 11.2.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from subprocess_tee import run
>>> run('sleep 10', shell=True, timeout=.1, capture_output=True)
CompletedProcess(args='sleep 10', returncode=0, stdout='', stderr='')

Whereas with subprocess.run the exception is correctly thrown:

Python 3.8.12 (default, Oct 27 2021, 12:52:48) 
[GCC 11.2.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from subprocess import run
>>> run('sleep 10', shell=True, timeout=.1, capture_output=True)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python3.8/subprocess.py", line 495, in run
    stdout, stderr = process.communicate(input, timeout=timeout)
  File "/usr/local/lib/python3.8/subprocess.py", line 1028, in communicate
    stdout, stderr = self._communicate(input, endtime, timeout)
  File "/usr/local/lib/python3.8/subprocess.py", line 1869, in _communicate
    self._check_timeout(endtime, orig_timeout, stdout, stderr)
  File "/usr/local/lib/python3.8/subprocess.py", line 1072, in _check_timeout
    raise TimeoutExpired(
subprocess.TimeoutExpired: Command 'sleep 10' timed out after 0.1 seconds

The output should have been a TimedoutException.

Also tried

>>> run(['sleep','10'], shell=False, timeout=.1, capture_output=False)
CompletedProcess(args=['sleep', '10'], returncode=0, stdout='', stderr='')

[bigbitbus]

We could add something like the below in

subprocess-tee/src/subprocess_tee/__init__.py

Line 97 in c1b4510

(can send PR if we agree)

            )
        if kwargs.get("timeout", -1):
            await asyncio.wait_for(process.wait(), timeout=kwargs.get("timeout", -1))

[ssbarnea]

Sounds ok, but please include a test.