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mergeTwoSortedArray.cpp
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mergeTwoSortedArray.cpp
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// Source : https://oj.leetcode.com/problems/merge-sorted-array/
// Author : Hao Chen
// Date : 2014-06-20
/**********************************************************************************
*
* Given two sorted integer arrays A and B, merge B into A as one sorted array.
*
* Note:
* You may assume that A has enough space (size that is greater or equal to m + n)
* to hold additional elements from B. The number of elements initialized in A and B
* are m and n respectively.
*
**********************************************************************************/
#include <stdio.h>
void merge(int A[], int m, int B[], int n) {
int ia = m-1 ;
int ib = n-1 ;
int i = m + n - 1;
for (int i=m+n-1; i>=0; i--){
if (ia>=0 && ib<0){
break;
}
if (ia<0 && ib>=0){
A[i] = B[ib--];
continue;
}
if (ia>=0 && ib>=0){
if (A[ia] > B[ib]){
A[i] = A[ia--];
}else{
A[i] = B[ib--];
}
}
}
}
void printArray(int A[], int n) {
printf("{");
for(int i=0; i<n; i++) {
printf("%d, ", A[i]);
}
printf("}\n");
}
int main()
{
int a[]={2,4,6,8,10,0,0,0};
int b[]={1,3,5};
merge(a, 5, b, 3 );
printArray(a, sizeof(a)/sizeof(int));
int a1[]={2,4,0,0,0};
int b1[]={3,5,7};
merge(a1, 2, b1, 3 );
printArray(a1, sizeof(a1)/sizeof(int));
int a2[]={12,14,16,18,20,0,0,0};
int b2[]={1,3,5};
merge(a2, 5, b2, 3 );
printArray(a2, sizeof(a2)/sizeof(int));
int a3[]={2,0};
int b3[]={3,};
merge(a3, 1, b3, 1 );
printArray(a3, sizeof(a3)/sizeof(int));
int a4[]={0,0,0};
int b4[]={1,3,5};
merge(a4, 0, b4, 3 );
printArray(a4, sizeof(a4)/sizeof(int));
int a5[]={2,4,6,8,10,0,0,0};
int b5[]={11,13,15};
merge(a5, 5, b5, 3 );
printArray(a5, sizeof(a5)/sizeof(int));
int a6[]={2,4,0,0,0,0,0,0};
int b6[]={1,3,5,7,9,11};
merge(a6, 2, b6, 6 );
printArray(a6, sizeof(a6)/sizeof(int));
return 0;
}