-
Notifications
You must be signed in to change notification settings - Fork 4.9k
/
LexicographicallySmallestStringAfterApplyingOperations.cpp
106 lines (98 loc) · 3.38 KB
/
LexicographicallySmallestStringAfterApplyingOperations.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
// Source : https://leetcode.com/problems/lexicographically-smallest-string-after-applying-operations/
// Author : Hao Chen
// Date : 2021-03-24
/*****************************************************************************************************
*
* You are given a string s of even length consisting of digits from 0 to 9, and two integers a and b.
*
* You can apply either of the following two operations any number of times and in any order on s:
*
* Add a to all odd indices of s (0-indexed). Digits post 9 are cycled back to 0. For example,
* if s = "3456" and a = 5, s becomes "3951".
* Rotate s to the right by b positions. For example, if s = "3456" and b = 1, s becomes
* "6345".
*
* Return the lexicographically smallest string you can obtain by applying the above operations any
* number of times on s.
*
* A string a is lexicographically smaller than a string b (of the same length) if in the first
* position where a and b differ, string a has a letter that appears earlier in the alphabet than the
* corresponding letter in b. For example, "0158" is lexicographically smaller than "0190" because the
* first position they differ is at the third letter, and '5' comes before '9'.
*
* Example 1:
*
* Input: s = "5525", a = 9, b = 2
* Output: "2050"
* Explanation: We can apply the following operations:
* Start: "5525"
* Rotate: "2555"
* Add: "2454"
* Add: "2353"
* Rotate: "5323"
* Add: "5222"
* Add: "5121"
* Rotate: "2151"
* Add: "2050"
* There is no way to obtain a string that is lexicographically smaller then "2050".
*
* Example 2:
*
* Input: s = "74", a = 5, b = 1
* Output: "24"
* Explanation: We can apply the following operations:
* Start: "74"
* Rotate: "47"
* Add: "42"
* Rotate: "24"
* There is no way to obtain a string that is lexicographically smaller then "24".
*
* Example 3:
*
* Input: s = "0011", a = 4, b = 2
* Output: "0011"
* Explanation: There are no sequence of operations that will give us a lexicographically smaller
* string than "0011".
*
* Example 4:
*
* Input: s = "43987654", a = 7, b = 3
* Output: "00553311"
*
* Constraints:
*
* 2 <= s.length <= 100
* s.length is even.
* s consists of digits from 0 to 9 only.
* 1 <= a <= 9
* 1 <= b <= s.length - 1
******************************************************************************************************/
class Solution {
private:
unordered_map<string, bool> processed;
void rotate_str(string& s, int n) {
std::rotate(s.begin(), s.begin()+n, s.end());
}
void add_str(string& s, int n) {
for(int i=1; i<s.size(); i+=2) {
s[i] = (s[i] -'0' + n) % 10 +'0';
}
}
public:
string findLexSmallestString(string s, int a, int b) {
string result = s;
dfs(s, a, b, result);
return result;
}
void dfs(string& s, int a, int b, string& result) {
if (processed.find(s) != processed.end()) return;
processed[s] = true;
if (s < result) result = s;
string str = s;
rotate_str(str, b);
dfs(str, a, b, result);
str = s;
add_str(str, a);
dfs(str, a, b, result);
}
};