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NthNodeFromEndOfList.cpp
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NthNodeFromEndOfList.cpp
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#include<bits/stdc++.h>
using namespace std;
struct ListNode {
int val;
ListNode *next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode *next) : val(x), next(next) {}
};
// * Brute Force, O(N) - Double PASS :-
ListNode* removeNthFromEnd(ListNode* head, int n) {
int size = 0;
ListNode *temp = head;
while(temp){
temp = temp->next;
size++;
}
int k = size - n;
ListNode* slow = head, *prev = NULL;
int cnt = 0;
while(slow && cnt < k){
prev = slow;
slow = slow->next;
cnt++;
}
if(prev){
prev->next = slow->next;
delete slow;
}else {
prev = slow;
slow = slow->next;
head = slow;
delete prev;
}
return head;
}
// * Optimised Approach O(N) time, - SINGLE PASS
ListNode* removeNthFromEnd(ListNode* head, int n) {
ListNode * slowPtr = head, * fastPtr = head, *prev = NULL;
int cnt = 1;
// * Maintain K-Distance b/w two ptrs
while(fastPtr && cnt < n){
fastPtr = fastPtr->next;
cnt++;
}
// * Move till last node
while(fastPtr && fastPtr->next){
fastPtr = fastPtr->next;
prev = slowPtr;
slowPtr = slowPtr->next;
}
// * We're not on Head Node
if(prev) {
prev->next = slowPtr->next;
delete slowPtr;
} else { // * If we're on HEAD then ChangeLinks !
prev = slowPtr;
slowPtr = slowPtr->next;
head = slowPtr;
delete prev;
}
return head;
}