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  1. Clone Graph

中等

https://leetcode-cn.com/problems/clone-graph/

Given a reference of a node in a connected undirected graph.

Return a deep copy (clone) of the graph.

Each node in the graph contains a value (int) and a list (List[Node]) of its neighbors.

class Node {
    public int val;
    public List<Node> neighbors;
}

Test case format:

For simplicity, each node's value is the same as the node's index (1-indexed). For example, the first node with val == 1, the second node with val == 2, and so on. The graph is represented in the test case using an adjacency list.

An adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.

The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.

Example 1:

Input: adjList = [[2,4],[1,3],[2,4],[1,3]]
Output: [[2,4],[1,3],[2,4],[1,3]]
Explanation: There are 4 nodes in the graph.
1st node (val = 1)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
2nd node (val = 2)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
3rd node (val = 3)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
4th node (val = 4)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).

Example 2:


Input: adjList = [[]]
Output: [[]]
Explanation: Note that the input contains one empty list. The graph consists of only one node with val = 1 and it does not have any neighbors.

Example 3:

Input: adjList = []
Output: []
Explanation: This an empty graph, it does not have any nodes.

Constraints:

The number of nodes in the graph is in the range [0, 100].
1 <= Node.val <= 100
Node.val is unique for each node.
There are no repeated edges and no self-loops in the graph.
The Graph is connected and all nodes can be visited starting from the given node.

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相关标签

  • Depth-First Search
  • Breadth-First Search
  • Graph
  • Hash Table

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O(n)

"""
# Definition for a Node.
class Node:
    def __init__(self, val = 0, neighbors = None):
        self.val = val
        self.neighbors = neighbors if neighbors is not None else []
"""

class Solution:
    def cloneGraph(self, node: 'Node') -> 'Node':
        if not node:
            return None

        # get all nodes then copy all nodes
        allOldNodesSet = self.getAllNodes(node)
       
        # create new nodes and map old node to new node
        old2NewMap = {}
        for oldnode in allOldNodesSet:
            old2NewMap[oldnode] = Node(oldnode.val)

        # copy neighbors
        for oldnode in allOldNodesSet:
            newnode = old2NewMap[oldnode]
            for oldneighbor in oldnode.neighbors:
                newneighbor = old2NewMap[oldneighbor]
                newnode.neighbors.append(newneighbor)

        # return new root node
        return old2NewMap[node]


    def getAllNodes(self, root):
        queue = collections.deque([root])
        allOldNodesSet = set([root])
        while queue:
            currnode = queue.popleft()
            for neighbor in currnode.neighbors:
                if neighbor in allOldNodesSet:
                    continue
                allOldNodesSet.add(neighbor)
                queue.append(neighbor)
        return allOldNodesSet