Skip to content

Symmetric contractions which are element-dependent vs. not #38

Answered by ilyes319
chaitjo asked this question in Q&A
Discussion options

You must be logged in to vote

Your understanding is completly correct! The equation to look at is actually Eq.11n You can see that the weights there have a z_i index. In the algo these are selected by the one hots as you mentionned.

While it is true that you would have the flexibility already, the full formulation is actually more flexible (the other would be a sort of tensor decomposition of what we are doing). Empirically it also gives the best results, for no extra cost!

Replies: 2 comments 2 replies

Comment options

You must be logged in to vote
2 replies
@chaitjo
Comment options

@ilyes319
Comment options

Comment options

You must be logged in to vote
0 replies
Answer selected by chaitjo
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Category
Q&A
Labels
None yet
2 participants